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4.905x^2-2.74x-12=0
a = 4.905; b = -2.74; c = -12;
Δ = b2-4ac
Δ = -2.742-4·4.905·(-12)
Δ = 242.9476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.74)-\sqrt{242.9476}}{2*4.905}=\frac{2.74-\sqrt{242.9476}}{9.81} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.74)+\sqrt{242.9476}}{2*4.905}=\frac{2.74+\sqrt{242.9476}}{9.81} $
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